Question

solve the following questions please .
prove that .​

Answer 1

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Answer 2

Answer:

Given : In trapezium ABCD , AB || DC. OC is the point of intersection of AC and BD.

To prove : OA/OC = OB/OD

Proof :

In ΔAOB and ΔCOD

∠AOB  = ∠COD    

[Vertically opposite angles]

∠OAB   = ∠OCD    

[alternate interior angles]

Then, ΔAOB∼ΔCOD

Therefore, OA/OC = OB/OD    

OA/OC = OB/OD    [Since, triangles  are Similar ,hence, corresponding Sides will be proportional]