Question

Solve the following questions:(Show all steps )(Pythagoras theorem) a) A ladder 26 m long is resting against a vertical wall. The foot of the ladder is 10m away from the base of the wall. How high up the wall will the ladder reach?

Answer 1

Well that is simple

Follow my steps

Given, a ladder 26 m long is resting against a vertical wall. The foot of the ladder is 10m away from the base of the wall.

Let Height of wall reached by ladder be x

So by Pythagorean theorem

Length of ladder^2 = Distance from base of wall^2 + Height of wall reached by ladder^2

So

${26}^{2} = {10}^{2} + {x}^{2}$

$676 = 100 + {x}^{2}$

$576 = {x}^{2}$

$\sqrt{576} = x$

$24 = x$

Thus 24 is required answer