solve the following recurrence relation Sn=2Sn-1
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HELLO DEAR,
RECURRENCE RELATION: A sequence can be defined by giving a general formula for its nth term or by writing few of its term.
An alternative approach is to write the sequence by finding a relationship is called a recurrence relation.
GIVEN: Sn = 2S(n-1) { n_> 2 }
{S1= 1. }
To solve the recurrence relation.
SOLUTION: Sn= 2S(n-1)
taking n=2
S2= 2S(2-1)
S2= 2S1
S2= 2×1
S2= 2.
taking n=3
S3=2S(3-1)
S3=2S2
S3=2×2
S3=4.
taking n=4
S4=2S(4-1)
S4=2S3
S4=2×4
S4=8.
taking n=5
S5= 2S(5-1)
S5=2S4
S5=2×8
S5=16.
taking n=6
S6=2S(6-1)
S6=2S5
S6=2×16
S6=32.
Therefore the recurrence relation is
{1,2,4,8,16,32,..........}
I HOPE IT'S HELP YOU DEAR,
THANKS.
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