Question

solve the following
request

Answer 1

Step-by-step explanation:

$\sin(2 \alpha ) = \cos( \alpha - 6) \\ \cos(90 - 2 \alpha ) = \cos( \alpha - 6) \\ 90 - 2 \alpha = \alpha - 6 \\ 90 + 6 = \alpha + 2 \alpha \\ 96 = 3 \alpha \\ \alpha = \frac{96}{3} = 32 \\ \alpha = 32$

iam taking theta as alpha okk

answer is 32