Math, asked by bhilanganajrchanda24, 9 months ago

Solve the following :
Sanjiv has Rs. 3.10 in 10-paisa and 25-paisa coins .If the 10-paisa coins exceed the number of 25-paisa coins by three,how many coins of each does he have?
Please give me soon.

Answers

Answered by Genius4522

3

Answer:

11coins and 8 coins

Step-by-step explanation:

Let the number of 25-paisa coins is x

So, the number of 10-paisa coins will be x+3

Rs.=P. 3.10×100=310P

According to question:-

25(x)+10(x+3)=310

25x+10x+30=310

35x=310-30

35x=280

x=280/35

x=8

Thus, 25-paisa coins=x=8 and 10-paisa coins=x+3=8+3=11

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