Question

solve the following set of simultaneous equations

(2×+y=5; 3x-y=5)​

Answer 1

$\large{x + y = 4 \: \: \: \: ...(i)}$

$\large{2x - 5y = 1 \: \: \: \: \: \: \: \: \: \: (ii)}$

$\small{ \sf{ \orange{from \: (i) \: we \: have}}}$

$\large{x = 4 - y}$

$\large{ \red{ \sf{putting \: the \: value \: of \: x \: in(ii)}}}$

$\large{2(4 - y) - 5y = 1}$

$\large{ \implies{8 - 2y - 5y = 1}}$

$\large{ \implies{8 - 7y = 1}}$

$\large{ \implies{8 - 1 = 7y}}$

$\large{ \implies{7 = 7y}}$

$\large{ \implies{ y = 1}}$

$\large{ \red{putting \: the \: value \: of \: y \: in(i) \: we \: have}}$

$\large{ \sf{x + 1 = y}}$

$\large{ \implies{x = 3}}$

$\large{ \sf{ \green{thus \: \: (x = 3) \: \: \: (y = 1)}}}$

hops its help u

ur solving practice set 5.1

Answer 2

Answer:

2x + y= 5

3x - y = 5

Adding I and II

5x = 10

X= 2

Putting the value of x in (I)

2 x 2+ y = 5

= 4 +y = 5

= y = 1

Hope it helps you keep smiling :)

X= 2 and y = 1