Question

Solve the following sets of simultaneous equations. 2x + 3y + 4 = 0 ; x - 5y = 11
​

Answer 1

Required Answer:-

Given:

• 2x + 3y + 4 = 0
• x - 5y = 11

To find:

• The value of x and y.

Solution:

We have,

➡ 2x + 3y + 4 = 0 .....(i)

➡ x - 5y = 11 .....(ii)

From (ii),

➡ x = 5y + 11

Substituting the value of x in equation (i), we get,

➡ 2(5y + 11) + 3y + 4 = 0

➡ 10y + 22 + 3y + 4 = 0

➡ 13y + 26 = 0

➡ 13y = -26

➡ y = -2

Putting the value of y, we get,

➡ x = 5 × (-2) + 11

➡ x = 11 - 10

➡ x = 1

★ Hence, the value of x and y are 1 and -2.

Answer:

• The value of x and y are 1 and -2.

Verification:

Lets verify our result.

When x = 1 and y = -2

2x + 3y + 4

= 2 × 1 + 3 × (-2) + 4

= 2 - 6 + 4

= -4 + 4

= 0 which is correct.

Again,

x - 5y

= 1 - 5 × (-2)

= 1 + 10

= 11 which is also correct.

Hence, our answers are correct (Verified ✔)

Answer 2

Answer:

=> The value of x is 1, and y is -2.

Step-by-step explanation:

Given that:-

$2x + 3y + 4 = 0$      $...(i)$

$x - 5y = 11$

$x=11+5y$            $...(ii)$

Substitute value of $x$ from ( 1 ) in the above equation, we get

=> 2 ( 11 + 5y ) + 3y = −4

=> 22 + 10y + 3y = −4

=> 10y + 3y = − 4 − 22

=> 13y = −26

Divide by $13$, on both sides we get

=> y = -2

So, the value of y is -2.

Putting value of y in ( 1 ) ,we get

=> $x=11+5y$

$=> x=11+5\times (-2)$

=> $x=11-10$

=> $x=1$

So, the value of x is 1.