solve the following sets of simultenous equation by elemination method
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21
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2x + y = 5 …(i)
3x – y = 5 …(ii)
Adding equations (i) and (ii),
2x + y = 5 + 3x – y = 5
5x = 10
∴ x = 10/5
∴ x = 2
Substituting x = 2 in equation (i),
2(2) + y = 5
4 + y = 5
∴ y = 5 – 4 = 1
∴ (2, 1) is the solution of the given equations.
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Answered by
1
Answer:
x = 2
y = 1
Step-by-step explanation:
2x + y = 5
3x - y = 5
5x = 10
=> x = 10/5
=> x = 2
Substituting the value of x we get:-
2×2 + y = 5
=> 4 + y = 5
=> y = 5 - 4
=> y = 1
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