Question

solve the following simaltaneous equation . 4m+3n=18,3m-2n=5​

Answer 1

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QUESTION:-

solve the following simaltaneous equation . 4m+3n=18,3m-2n=5

SOLUTIONS:-

4m+3n =18 ---(1)

3m -2n = 5 ---(2)

we solve this equation by using value putting method..

• from (1)

● 4m + 3n = 18

$● \: n = \frac{18 - 4m}{3} \: \: \: \: -- (3)$

• put this value in (2)....

● 3m - 2n = 5

$● \: 3m \: - 2( \frac{18 - 4m}{3} ) = 5$

$● \: 3m - \frac{(36 - 8m)}{3} = 5$

$● \: \frac{9m - 36 + 8m}{3} = 5$

● 17m -36 = 15

● 17m = 15+36

● 17m = 51

● m = 3

• now , put m = 3 in (3)

$● \: n \: = \frac{18 - 4m}{3}$

$● \: n \: = \frac{18 - 4(3)}{3}$

$● \: n = \frac{18 - 12}{3}$

$● \: n \: = \: \frac {6}{3}$

● n = 2

ANSWER:-

so the answer is m = 3 & n = 2 .