Math, asked by adityamishra9846, 1 year ago

Solve the following simiutaneous equation2x+y=1;x+3y=-7

Answers

Answered by ankita3838
2

Answer:

2x+y=1..............................(i)

x+3y=-7.............................(ii)

From equation (i), y=1-2x

Putting the value of y in equation (ii),

x+3(1-2x)=-7

x+3-6x=-7

-5x=-7-3

-5x=-10

x=2

Putting the value of x in equation (i)

2(2)+y=1

4+y=1

y=-3

Answered by Anonymous
2

Answer:

Y = –3

Step-by-step explanation:

2x + y = 1 ............(1)

x + 3y = –7...........(2)

from equation (1)

2x + y = 1

y = 1–2x

putting the value of y in equation (2)

x + 3(1–2x) = –7

x +3 - 6x = –7

–5x = –7–3

–5x = –10

X = 2

putting the value of x in equation (1)

2x + y = 1

2(2) + y = 1

4+y = 1

Y = –3

Hope this helps !!

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