Question

Solve the following simultaneous equ
(1) 3a + 5b = 26; a + 5b = 22​

Answer 1

Answer : first step

Solution :-

3a + 5b = 26 ....................(1)

a + 5b = 22 ......................(2)

Subtracting (2) from (1), we get

3a + 5b = 26

a + 5b = 22

- - -

____________

2a = 4

____________

⇒ 2a = 4

⇒ a = 4/2

⇒ a = 2

Substituting the value of a = 2 in (2), we get.

a + 5b = 22

⇒ 2 + 5b = 22

⇒ 5b = 22 - 2

⇒ 5b = 20

⇒ b = 20/5

⇒ b = 4

So. the value of a is 2 and the value of b is 4

Second step : Answer to the question :

Given,

3a+5b= 26; a+5b= 22

So, 3a+5b=26 ------- (1)

and a+5b=22 -------(2)

Now

(1)×1=> 1×(3a+5b)=1×26

=> 3a+5b=26 --------(3)

(2)×3 => 3(a+5b)=3×22

=> 3a+15b=66 ---------(4)

Hence, (4)-(3)

3a+15b-(3a+5b) = 66-26

=> 3a+15b-3a-5b = 40

=> 15b-5b = 40

=> 10b = 40

=> b = 40/10

=> b = 4

We have already found the value of b = 4 so to find the value of a we will put the value of b in (1), Let's see what will be the answer.

3a+5(4) =26

=> 3a+20 =26

=> 3a = 26-20

=> 3a = 6

=> a = 6/3

=> a = 2

Hence the value of a is 2 and the value b is 4

Note that you can also put the value of b in (2) to find the value of a.

a+5×4 =22

=> a+20=22

=> a = 22-20

=> a= 2

hope it helps u...

Answer 2

Step-by-step explanation:

Given :-

• 3a + 5b = 26

• a + 5b = 22

To find :-

• Find the value of a and b

Solution :-

Solve it by elimination method

3a + 5b = 26 ---(i)

a + 5b = 22 ----(ii)

Subtract both the equations

→ 3a + 5b - (a + 5b) = 26 - 22

→ 3a + 5b - a - 5b = 4

→ 2a = 4

→ a = 4/2

→ a = 2

Put the value of a in equation (ii)

→ a + 5b = 22

→ 2 + 5b = 22

→ 5b = 22 - 2

→ 5b = 20

→ b = 20/5

→ b = 4

Hence,

Required values

a = 2 and b = 4