Question

solve the following simultaneous equation. 1/ 3 x+ y + 1/ 3 x -y =3/4 ; 1/ 12(3 x +y ) - 1/2(3 x -y ) = -1/8​

Answer 1

Answer:

(3×-y)=-1/8) answer (3-+y 8) 15

Answer 2

$\frac{1}{3} x + y + \frac{1}{3} x - y = \frac{3}{4} \\ \\ \frac{2x}{3} = \frac{3}{4} \\ \\ 2x = \frac{3}{4} \times 3 \\ \\ 2x = \frac{9}{4} \\ \\ x = \frac{9}{4} \times \frac{1}{2} \\ \\ x = \frac{9}{8}$

$\\ \\ \\ \\ \\ \frac{1}{12} (3x + y) - \frac{1}{2} (3x - y) = - \frac{1}{8} \\ \\ \frac{x}{4} + \frac{y}{12} - \frac{3x}{2} + \frac{y}{2} = - \frac{1}{8} \\ \\ \frac{x - 6x}{4} + \frac{y + 6y}{12} = - \frac{1}{8} \\ \\ \frac{ - 2x}{2} + \frac{2y}{2} = - \frac{1}{8} \\ \\ - x + y = - \frac{1}{8} \\ \\ x + y = \frac{1}{8}$