Math, asked by pramodpawar79479, 4 months ago

Solve the following simultaneous equation
(1) 3a + 3b = 26; a + 5b = 22
(3) 2x - 3y = 9: 2x + y = 13
(5) 5x + 2y = -3; x + 5y = 4​

Answers

Answered by arkaanmalik6789
0

Answer:

(1) 3a + 3b = 26; a = 22-5b

3(22-5b) + 3b = 26

66- 15b +3b = 26

66-12b = 26

-12b = 26-66

-12b = -40

b = 10/3

a = 22-5b

a= 22-5(10/3)

a = 22-50/3

a = 16/3

Answered by cutepay1017
0

Answer:

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Step-by-step explanation:

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