solve the following simultaneous equation:-1)4x+3y=18;3x-2y=5
Answers
Answered by
5
4x + 3y = 18 and 3x -2y = 5
Sol: x = 3 & y = 2
Step-by-step explanation:
4x + 3y = 18 - eq 1
3x -2y = 5 - eq 2
Multiplying Eq 1 by 2 & eq 2 by 3
8x + 6y = 36
9x - 6y = 15
Elimination y by Adding both
17x = 51
x = 3
now substituting value of x into Eq 1
4*3 + 3y = 18
=> 3y = 6
=> y = 2
Sol: x = 3 & y = 2
Step-by-step explanation:
4x + 3y = 18 - eq 1
3x -2y = 5 - eq 2
Multiplying Eq 1 by 2 & eq 2 by 3
8x + 6y = 36
9x - 6y = 15
Elimination y by Adding both
17x = 51
x = 3
now substituting value of x into Eq 1
4*3 + 3y = 18
=> 3y = 6
=> y = 2
Answered by
4
Solving by elimination method
Considering y
LCM is 6
So multiply equation 1 by 2 and equation 2 by 3
8x + 6y = 36
9x - 6y = 15
Since signs are opposite we will add
17x = 51
x = 3
Therefore,
4(3) + 3y = 18
3y = 6
y = 2
Considering y
LCM is 6
So multiply equation 1 by 2 and equation 2 by 3
8x + 6y = 36
9x - 6y = 15
Since signs are opposite we will add
17x = 51
x = 3
Therefore,
4(3) + 3y = 18
3y = 6
y = 2
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