Question

solve the following simultaneous equation 1/x+1/y=12;3/x-2/y =1

Answer 1

let us take 1/x as p
and
1/y as q

acc/question
p+q=12. and

3p-2q=1

=> acc to elimination method

(p+q. = 12)2.

(3p-2q= 1)1
__________
2p+2q=24
3p-2q=1
_________
5p. =25
p. =25/5=5

so we got 5=p
then 3p-2q=1. substitute the value of p
=>15-2q=1
-2q=1-15
-2q=-14
q= -14/-2=7. now q we get as 7
therefore 1/x=5. =>x=1/5
1/y=7. =>y=1/7

Answer 2

1/x+1/y=12

x+y=12xy-------(1)


3/x-2/y = 1

3y-2x = xy -------(2)

By multiplying with 3 in equation (1)

3x+3y = 36xy------(3)
-2x+3y = xy --------(2)
+ - -
__________________ By substraction


x= 35xy

xy = x/35

y= x/ 35x

y= 1/35



By putting the value of y in equation (1)

x+1/35 = 12x × 1/35

x= 12x/35-1/35

x= 12x-1/35

35x= 12x-1

35x-12x = -1

23x = -1

x= -1/23


_________________
x= -1/23 & y= 1/35
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Hope it will help you ☺❤