Question

solve the following simultaneous equation 2x+3y+2=0 and 2xy=-1​

Answer 1

Answer:

We're asked to find the separate value of "x" & "y". Check explanation for the complete method.

Step-by-step explanation:

2x+3y+2= 0 (eq. 1)

2xy= -1 (eq. 2)

Sol:

Taking eq.2

2xy= -1

÷ing both sides of eq. by " 2x"

2xy/2x = -1/2x

after cancelling we've left with

y= -1/2x ( eq. A)

Now put eq. A into eq. 1

2x+3y+2=0

2x + 3(-1/2x) + 2 = 0

2x - (3/2)x + 2 = 0

+ing (-2) on both sides of eq.

2x -(3/2)x + (-2) + 2 = +(-2)

2x - (3/2)x = -2

taking "x" common & solving by taking L.C.M of L.H.S of the above eq.

x( 4-3/2) = -2

(1/2)x = -2

now Xing b.s of eq. by 2

we got

x = -4

Now put x = -4 in eq. A

2(-4) + 3y + 2 = 0

-8 + 3y + 2= 0

(-8+2) + 3y = 0

-6 + 3y = 0

subtract (-6) on b.s of eq.

-6 - (-6) +3y = -6

-6 +6 + 3y = -6

3y = -6

÷ing 3 on b.s of eq.

so,

3y/3 = -6/3

y= -2

Answer: x= -4, y= -2