solve the following simultaneous equation 2x+3y=5 and x²+xy-2y²=10
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Answer:
use substitution
from the second equation y = (-1-2x) / 3. Plug this into the first equation:-
x^2 + x(-1-2x) + 2(-1-2x)^2 = 4
-------- --------
3 9
multiply through by 9:-
9x^2 + 3x(-1 - 2x) + 2(-1-2x)^2 = 36
9x^2 - 3x - 6x^2 + 2(1 + 4x + 4x^2) = 36
9x^2 - 3x - 6x^2 + 2 +8x + 8x^2 = 36
11x^2 +5x -34 = 0
which you can solve using the quadratic formula
- Then substitute the 2 values of x into the second equation to find values of y.pls mark me as brainilist.
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