Math, asked by akshisaha06, 1 year ago

Solve the following Simultaneous equation :-
3/x+y + 2/x-y = 3
2/x+y + 3/x-y = 11/3

Answers

Answered by kajal10105
256
let 1/x+y be p
1/x-y be q
so the eqn is
3p+2q=3
2p+3q=11/3

Eliminate the equation
2[3p+2q=3] ------------1
3[2p+3q=11/3]----------2

subtract the equation
6p+4q=6
6p+9q=11
_ _ _
___________
-5q=-5
q=-5/-5
q=1

put the value of q in eqn 1
6p+4q=6
6p+4(1)=6
6p+4=6
6p=6-4
6p=2
p=2/6
p=1/3


1/x+y=p=1/3
1/x+y=1/3
3=x+y--------------3rd eqn

1/x-y=q=1
1/x-y=1
x-y=1---------4th eqn
x=1+y

put the value of x in eqn 3rd
3=x+y
3=1+y+y
3=1+2y
3-1=2y
2=2y
2/2=y
y=1

put the value of y in eqn 4th
x=1+y
x=1+1
x=2

akshisaha06: Thanks a lot Dear !!!
Answered by Aditiiiiiiiiiii
40

Answer:

x= 2 & y = 1

Step-by-step explanation:

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