Question

solve the following simultaneous equation 3a-2b=-10; 2a+3b=2 by special method
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Answer 1

Step-by-step explanation:

3a−2b=−10;2a+3b=2

a=

3

2b−10

⇒ Put it in second equation.

2×

3

2b−10

+3b=2

4b−20+9b=6

13b=26

∴b=2

a=

3

2b−10

=

3

2(2)−10

=−2

a=−2 and b=2

Answer 2

Answer:

3a-2b= -10 ____x

2a+3b=2______y

so

multiply by 2 in x

And

multiply by 3 in y

for balence this equ..

then

6a-4b=-20___x

6a+9b=6___y

then

subtract y from x

6a-4b=-20

6a+9b=6

- - -

-13b=-26

b= 2

then

put the value of b in equ.x

3a-2×2=-10

3a-4=-10

3a=-10+4

3a=-6

a=-2

so,

a=-2, b=2