solve the following simultaneous equation : 3a+5b=26 , a+5b=22 by using substitution method.
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3a + 5b = 26; .....(I)
a + 5b = 22 .....(II)
Subtracting (II) from (I)
2a = 4
⇒ a = 2
Putting the value of a = 2 in (II)
5b = 22 - 2 = 20
⇒b = 20/5
=4
Thus, a = 2 and b = 4.
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