Solve the following simultaneous
equation: 3a + b = 3; 7a + 3b= 7.
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3a+b =3;7a+3b=7
3(3a+b)=3×3
9 a +3b=9
Therefore,(9a+3b)(7a+3b)=9-7
2a=2
a =1
b=3-3a=3-3=0
a =1 and b=0
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