Question

solve the following simultaneous equation
3x-4y=10,4x+3y=5​

Answer 1

heya friend

here is your answer

===========================

let,

3x-4y = 10 ----------> {1}

4x+3y = 5 ------------> {2}

{1} × 3 = 9x - 12y = 30

{2} ×4 = 16x + 12y = 20
====================
= 25x = 50

x = 50/25

x = 2

therefore , x = 2

now place x in eq 1

(3×2) - 4y = 10

6 - 4y = 10

-4y = 4

y = (-1)


sho ,

x = 2
y = (-1)


i hope it helped uh !!

thanks

Answer 2

3x-4y = 10 ----------> {1}

4x+3y = 5 ------------> {2}

{1} × 3 = 9x - 12y = 30

{2} ×4 = 16x + 12y = 20

====================

= 25x = 50

x = 50/25

x = 2

therefore , x = 2

now place x in eq 1

(3×2) - 4y = 10

6 - 4y = 10

-4y = 4

y = (-1)

sho ,

x = 2

y = (-1)

i hope it helped uh !!

thanks

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