solve the following simultaneous equation 5m-3n=19;m-6n=-7
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Answered by
22
5m-3n=19--------(1)
m-6n= -7-----------(2)
Multiplying (2) by 5,
5m-30n= -35-------(3)
Subtracting (3) from (1),
27n=54
n=2
Substituting n=2 in (1),
5m-6=19
5m=25
m=5
Hence, m=5, n=2
sudarshan38:
thank you very much
Answered by
0
Step-by-step explanation:
5m - 3n = 19 m - 6n = -7
10m - 6n = 38 m - 6n = -7
- SUBTRACT
10m - 6n - (m - 6n) = 38 - (-7)
10m - 6n - m + 6n = 38 + 7
9m = 45
m = 5
5 - 6n = -7
6n = 12
n = 2
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