Solve the following simultaneous equation 5x-6y=27 ; 3x-2=13
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3x-2=13
3x=13+2
3x=15
x=5
Substitute the value of x
5x-6y=27
5(5)-6y=27
25-6y=27
-6y=2
Y=-1/3
3x=13+2
3x=15
x=5
Substitute the value of x
5x-6y=27
5(5)-6y=27
25-6y=27
-6y=2
Y=-1/3
Answered by
0
Step-by-step explanation:
in your questions y is missing
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