Math, asked by aabedamaniyar, 21 hours ago

/Solve the following simultaneous equation. 99x + 101y =499 ; 101x + 99y =501
a) x = 7, y = 3 b) x = 3, y = 7 c) x = -7, y = -3 d) x = -3, y = -7

Answers

Answered by goremayuri28
0

Answer:

x-3 , y-2

Step-by-step explanation:

let the equation be a and b

adding equations a , b

you will get- 200x+200y= 1000

now divide this term by 200

you will get

x+y-5--------(1)

subtract equations a and b

-2x+2y =-2 (divide this term by 2)

x-y=1-----(2)

adding equations 1 and 2

your answer is 2x=6

=x-3

substitute this term in any equation

y-2

Answered by nishumasuda
0

Answer:

solution....

99x+101y=499 ------(1)×101

101x+99y=501-------(2)×99

adding both equations

we get,

9999x+10201y=50399

9999x+9801y=49599

- - -

---------------------------------

changing the sign.

so 9999x will be cancel

so, 400y=800

y=2

now putting the value of y in eq.(1)

so, 99x=499-202

x=297/99

X=3

answer

Similar questions