Question

Solve the following simultaneous equation by adding or subtracting the equation.

Answer 1

Step-by-step explanation:

1.(2x+2+y -2)/4=8

(2x+y)=32

2.(3x-12-2y+2)/12=1

(3x-2y-10)=12

3x-2y=12+10

3x-2y=22

Answer 2

Solution

Given :-

• (x+1)/2 + (y-2)/4 = 8 -----(1)
• (x-4)/4 - (y-1)/6 = 1 --------(2)

Find :-

• value of x & y

Explanation

By, equ(1)

==> (x+1)/2 + (y-2)/4 = 8

==> 4*(x+1) + 2*(y-2) = 8*8

==> 4x + 2y = 64 -------------(3)

Again, by equ(2)

==> (x-4)/4 - (y-1)/6 = 1

==> 3*(x-4) - 2*(y-1) = 12

==> 3x - 2y = 12 + 12 - 2

==> 3x - 2y = 22 ------------(4)

Add equ(1) & equ(2)

==> 4x + 3x = 64 + 22

==> 7x = 86

==> x = 86/7

Keep Value of x in equ(4)

==> 3 * 86/7 - 2y = 22

==> 2y = 258/7 - 22

==>2y = (258 - 154)/7

==>2y = 104/7

==>y = 104/(7*2)

==>y = 52/7

Hence

• Value of x be = 86/7
• Value of y be = 52/7

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