Question

solve the following simultaneous equation by substitution
method 3a+5b=26 and a+5b=22​

Answer 1

Answer:

Here is ur ans___________:)

3a+5b=26

a+5b=22

_________

on subtraction signs will change

3a+5b=26

-a-5b=-22

__________

2a=4

a=4/2

a=2

now substituting a=2 in equation 1

3×2+5b=26

6+5b=26

5b=26-6=20

b=20/5

b=4

so a=2 and b=4

hope it helps so pls mark as brainleist :)

Answer 2

Answer:

3a + 5b = 26; .....(I)

a + 5b = 22 .....(II)

Subtracting (II) from (I)

2a = 4

⇒ a = 2

Putting the value of a = 2 in (II)

5b = 22 - 2 = 20

⇒b = 20/5

=4

Thus, a = 2 and b = 4.