Math, asked by nadiageoffrey8, 3 months ago

solve the following simultaneous equation by substitution method
( 6p+q=15
(3p+q=9

Answers

Answered by gopalpvr
1

Answer:

so p=2,q=3

Step-by-step explanation:

6p+q=15--------1

q =15-6p

substitute this equation 2

3p+q=9--------2

3p+15-6p=9

15-3p=9

-3p=9-15

-3p=-6

p= -6/-3

p= 2

substitute q in equation 1

6×2+q=15

q=15-12=3

q=3

so p=2,q=3

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