solve the following simultaneous equation by substitution method
( 6p+q=15
(3p+q=9
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Answer:
so p=2,q=3
Step-by-step explanation:
6p+q=15--------1
q =15-6p
substitute this equation 2
3p+q=9--------2
3p+15-6p=9
15-3p=9
-3p=9-15
-3p=-6
p= -6/-3
p= 2
substitute q in equation 1
6×2+q=15
q=15-12=3
q=3
so p=2,q=3
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