Solve the following simultaneous equation for x and y
m(x+y) +n(x-y) - (m²+mn+n²) =0
n(x+y) +m(x-y) - (m²-mn+n²) =0
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Step-by-step explanation:
Let, (x+y)= T
(x-y)= Z
now, mT+nZ=m²+mn+n²......(1)
nZ+mT=m²-mn+n².......(2)
- - - +. -
2nZ=2mn
Z=2mn/2n
Z=m
put the value of Z in eqñ 1 , we get.
mT+nZ=m²+mn+n²
mT+nm=m²+mn+n²
mT=m²+mn+n²-mn
mT=m²+n²
T=m²+n²/m.
Again,
x+y=m²+n²/m......(3)
x-y=m...................(4)
2x= m²+n²/m-m
2x =n²/m
x=n²/2m answer.
now, put the value of x eqñ 4, we get.
n²/2m-y= m
n²/2m-m=y
y=n²-2m²/2m answer.
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