Question

solve the following simultaneous equation in in two variables by the method of elimination


​

Answer 1

$x + y = 48 \\ x + 4 = \frac{5}{2} y + \frac{20}{2}$

$x + y = 48 \\ x - \frac{5}{2} y = 10 - 4$

$x + y = 48 \\ x - (\frac{5}{2}y) = 6$

now applying elimination method..

$x + y = 48 \\ x - \frac{5}{2} y = 6 \\ - + \: \: \: \: \: - (sign \: change)$

so

$\frac{5}{2} y + y = 48 - 6 \\ \frac{5y + 2y}{ 2} = 42$

7y =42×2

y=84/7=12

thus y=12

put the value of y in

x+y=48

x+12=48

x=48-12

x=36

therefor x=36 and y=12✌☺✌