Solve the following simultaneous equation using cramer's rule 4x + 3y - 4 = 0 ; 6x = 8 - 5y
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Given, 4x + 3y - 4 = 0 -------(1)
6x = 8 - 5y
6x + 5y - 8 = 0 -------(2)
use Cramer's rule ,
4x + 3y - 4 = 0
6x + 5y - 8 = 0
for equations ,
\frac{x}{3\times-8-(-4)\times5}=\frac{-y}{4\times - 8-(-4)\times6}=\frac{1}{4\times5-3\times6}
3×−8−(−4)×5
x
=
4×−8−(−4)×6
−y
=
4×5−3×6
1
=> x/(-24 + 20) = -y/(-32+ 24) = 1/(20 - 18)
=> x/-4 = -y/-8= 1/2
=> x/-4 = y/8 = 1/2
=> x = -4/2 = -2 and y = 8/2 = 4
hence, x = -2 and y = 4
Step-by-step explanation:
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