Math, asked by sumitpatil25, 1 year ago

solve the following simultaneous equations : (1) 2x + 3y = 7 ; 2y - x = 0

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Answers

Answered by CoolestCat015
9

Hey dear here is your answer!!!!!


___________________________


Firstly, lets note down both the equations provided to us:-


2x + 3y = 7                        ...(1)

2y - x = 0


Multiply the second equation by two.


2(2y - x = 0 )

4y - 2x = 0                      ...(2)


Now, add both the equations (1) and (2) :-


( 2x + 3y ) + ( 4y - 2x ) = 7

2x + 3y + 4y - 2x = 7


Add the like terms:-


7y = 7

y = \frac{7}{7}

y = 1


Now, substitute the value of 'y' in any of the equations:-


2(1) - x = 0

2 - x = 0

- x = -2

x = 2


So, the value of 'x' and 'y' are 2 and 1 respectively !



\large\boxed{\large\boxed{\large\boxed{Solved !}}}}


❣️⭐ Hope it helps you dear...⭐⭐❣️❣️


sumitpatil25: thanks
CoolestCat015: no problem
Answered by rishabhruhigauri
0

Step-by-step explanation:

Firstly, lets note down both the equations provided to us:-

2x + 3y = 7 ...(1)

2y - x = 0

Multiply the second equation by two.

2(2y - x = 0 )

4y - 2x = 0 ...(2)

Now, add both the equations (1) and (2) :-

( 2x + 3y ) + ( 4y - 2x ) = 7

2x + 3y + 4y - 2x = 7

Add the like terms:-

7y = 7

y = \frac{7}{7}

7

7

y = 1

Now, substitute the value of 'y' in any of the equations:-

2(1) - x = 0

2 - x = 0

- x = -2

x = 2

So, the value of 'x' and 'y' are 2 and 1 respectively !

I hope you will like my answer

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