Question

Solve the following simultaneous equations
(1) 3a + 5b = 26; a + 5b = 22
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Answer 1

Hey your answer.

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Answer 2

Your answer is given -::

Solution :-

3a + 5b = 26 ....................(1)

a + 5b = 22 ......................(2)

Subtracting (2) from (1), we get

3a + 5b = 26

a + 5b = 22

- - -

____________

2a = 4

____________

⇒ 2a = 4

⇒ a = 4/2

⇒ a = 2

Substituting the value of a = 2 in (2), we get.

a + 5b = 22

⇒ 2 + 5b = 22

⇒ 5b = 22 - 2

⇒ 5b = 20

⇒ b = 20/5

⇒ b = 4

So. the value of a is 2 and the value of b is 4