Math, asked by shaikhkaif92222, 2 months ago

solve the following simultaneous equations : 1 upon 3x+2y=-18 ; 1 upon 3x+6y=30​

Answers

Answered by Animeshmukherjee1230
1

Answer:

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Answered by spiarani16
0

Answer:

x=-14

y=12

Step-by-step explanation:

3x+2y= -18

=> 3x=-18-2y

=> x= (-18-2y)/3

Now put value of x in 3x+6y=30

=> 3 * (-18-2y)/3 +6y=30

=> -18-2y+6y=30

=> 4y=48

=> y=12

Now put the value of y in 3x+2y=-18

=> 3x+2*12=-18

=> 3x+24=-18

=> 3x= -42

=> x=-14

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