Solve the following simultaneous
equations
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Answer:
4x+3y/12 = 4 & 40x -6y /48 =4
4x + 3y = 48 -----------1 & 40x -6y = 192 ------------ 2
multiplying 1 by 10
40x + 30y = 480 -------------------3
subtracting 2 from 3
40x - 40x + 30y -(-6y) = 480 - 192
36y = 288
y= 8
putting in 1
4x + 24 = 48
4x = 48-24
4x = 24
x= 6
option 1 (6,8) is correct
Step-by-step explanation:
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