Solve the following simultaneous
equations
3x+y = 10 ; x-y=2
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The given equations are;
3x + y = 10 . . . .(1)
x - y = 2 . . . . . (2)
Now,
Adding equations (1) and (2), we get,
➜ 3x + y + x - y = 10 + 2
➞ 3x + x + y - y = 12
➞ 4x = 12
➞ x = 12/4
➞ x = 3
Now,
Putting the value of x = 3 in equation (2), we get
➜ x - y = 2
➞ (3) - y = 2
➞ 3 - y = 2
➞ - y = 2 - 3
➞ - y = - 1
➞ y = 1
∴ The value of x = 3, y = 1 is the solution of the system of the given equations.
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