Question

solve the following simultaneous equations

Answer 1

Hope it will help you .

Answer 2

3a+5b=26........(1)
a+5b=22..........(2)
by elimination method,,,,
1*1, 3a+5b=26
2*3, 3a+15b=66
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            -10b= -40
        or, b = -40/ -10
        or, b = 4
a+5b = 22
or, a+5*4= 22( putting b =4)
or, a+20 = 22
or, a = 22-20
or, a = 2
therefore, a = 2
                 b = 4