Question

Solve the following simultaneous equations. 5x-3y=1 , 2x+5y-19=0​

Answer 1

Answer:

Hey......^_^

➡ Using substitution method

◾ 5x - 3y = 1 ... 1st equation

2x + 5y = 19

,OR

x = {19 - 5y } ÷ 2

Substituting the value of x in 1st equation

5 { 19-5y}÷2 - 3y = 1

{95 - 25y} ÷ 2 -3y -1 = 0

{95 - 25y - 6y - 2 } ÷ 2 = 0

{93 - 31y } = 0

31y = 93

↪↪ y = 3

Therefore

x = {19 - 5×3} ÷ 2

x = {19-15} ÷ 2

↪↪ x = 2

✌Hope it helps

Step-by-step explanation:

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Answer 2

Answer:

it's very easy

Step-by-step explanation:

5x-3y=1,2x+19=0

5x-3y-1=0, 2x+19=0

2x= -19

x= -19/2

5x-3y-1=0

x= -19/2

5( -19/2)-3y-1=0

-45/2-3y-1=0