solve the following simultaneous equations 7x-3y=1, 5x-2y=1????
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Step-by-step explanation:
Given :-
7x-3y=1, 5x-2y=1
To find :-
Solve the following simultaneous equations
Solution :-
Given pair of linear equations in two variables are
7x-3y = 1 -----------(1)
5x-2y = 1 ----------(2)
=>5x = 1+2y
=> x = (1+2y)/5 ----(3)
On Substituting the value of x in (1) then
=> 7[(1+2y)/5] - 3y = 1
=> [(7+14y)/5]-3y = 1
=> [(7+14y)-(3y×5)]/5 = 1
=>(7+14y-15y)/5 = 1
=> (7-y)/5 = 1
=> 7-y = 1×5
=> 7-y = 5
=> -y = 5-7
=> -y = -2
=>y = 2
On Substituting the value of y in (3)
x = (1+2y)/5
=> x = [1+2(2)]/5
=> x = (1+4)/5
=> x = 5/5
=> x = 1
Therefore, x = 1 and y = 2
Answer:-
The solution for the given problem is (1,2)
Check:-
If x = 1 and y = 2 then
LHS = 7x-3y
=> 7(1)-3(2)
=> 7-6
=> 1
=> RHS
LHS = RHS is true for x = 1 and y = 2
LHS = 5x-2y
=> 5(1)-2(2)
=> 5-4
=>1
=> RHS
LHS = RHS is true for x=1 and y = 2
Used Method:-
- Method of Substitution.
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