Question

Solve the following simultaneous equations a) 41m -47n = 35 47m - 41n=53​

Answer 1

Answer:

Step-by-step explanation: Firstly add both of the eq

41m-47n=35

+47m-41n=53

------------------------

=>88m-88n=88

------------------------

then divide by 88

=>m-n=1---->(1)

Now subtract both of them

41m-47n=35

-47m+41n=-53

----------------------

=>-6m-6n=-18

----------------------

then divide by 6

=>-m-n=-3----->(2)

the from eq 1 and 2

m-n=1

-m-n=-3

----------------------

=>-2n=-2

----------------------

    2n=2

      n=2/2

      n=1

sub n in eq 2

-m-1=-3

-m=-3+1

-m=-2

Therefore m=2 & n=1