Solve the following simultaneous equations. ax+by=5 and bx+ay=3. where a and b are constant.
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Step-by-step explanation:
ax+by = 5 …(1)
bx+ay = 3 … (2)
Multiply (1) by b and (2) by a to get
abx + b^2y = 5b … (3)
abx + a^2y = 3a … (4)
Subtract (3) from (4) to get
y(a^2-b^2) = 3a-5b, or
y = (3a-5b)/(a^2-b^2)
Multiply (1) by a and (2) by b to get
a^2x+aby = 5a …(5)
b^2x+aby = 3b … (6)
Subtract (6) from (5) to get
x(a^2-b^2) = 5a-3b, or
x = (5a-3b)/(a^2-b^2)
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