Solve the following simultaneous equations by using the elimination method:
2x + 3y = 13
3x + 2y = 12
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NeneAmaano:
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Hi,
2x+3y=13
(2x+3y)×2=13×2
4x+6y=26
and
3x+2y=12
(3x+2y)×3=12×3
9x+6y=36
(4x+6y=26)-(9x+6y=36)
-5x+0= -10
x=-10÷-5
x=2
putting value,
2×2+3y=13
4+3y=13
3y=9
y=9÷3
y=3
3×2+2y=12
6+2y=12
2y=6
y=3
Hope it will help you
Mark it as brainliest.
2x+3y=13
(2x+3y)×2=13×2
4x+6y=26
and
3x+2y=12
(3x+2y)×3=12×3
9x+6y=36
(4x+6y=26)-(9x+6y=36)
-5x+0= -10
x=-10÷-5
x=2
putting value,
2×2+3y=13
4+3y=13
3y=9
y=9÷3
y=3
3×2+2y=12
6+2y=12
2y=6
y=3
Hope it will help you
Mark it as brainliest.
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