Question

Solve the following simultaneous equations graphically x+y=4;2x-y=2​

Answer 1

Answer:

Answer:

Question

✳️Solve the following simultaneous equations graphically x+y=4;2x-y=2

solution ⬇️

✍️x+y=4..(1)

✍️2x-y=2..(2). {(-)(+)} sign will be cancelled

✍️3x=6.. Added equation 2 and 1

x=63=2x = \frac{6}{3} = 2x=

3

6

=2

✍️x=2

✳️ Substituting value x=2 in equation 1

✍️x+y=4..(1)

✍️2+y=4

✍️y=4-2

✍️y=2

️(x,y)(2,2) is the solution of the given quadratic

Step-by-step explanation:

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Answer 2

The answers to the simultaneous equations x + y = 4 and 2x - y = 2.

• We must draw the lines corresponding to each equation and locate the intersection of those lines in order to solve the simultaneous equations visually.

• By deducting x from both sides, the initial equation, x + y = 4, may be rewritten as y = -x + 4. By adding y to both sides of the second equation and dividing by -1, it may be expressed as y = 2x - 2.

• We can solve for y and give x any value to plot these lines. The point (0, 4) lies on the line, for instance, if we allow x = 0 in the first equation. The point (1, 3) also exists on the line if we allow x = 1, which gives us y = 3. To get extra points, we may repeat this procedure for different x values.

• The point (0, -2) is on the line if we let x = 0 in the second equation to get y = -2. The point (1, 0) also fits on the line if we allow x = 1, as this results in y = 0.

• We can solve for y and give x any value to plot these lines. The point (0, 4) lies on the line, for instance, if we allow x = 0 in the first equation. The point (1, 3) also exists on the line if we allow x = 1, which gives us y = 3. To get extra points, we may repeat this procedure for different x values.

• The point (0, -2) is on the line if we let x = 0 in the second equation to get y = -2. The point (1, 0) also fits on the line if we allow x = 1, as this results in y = 0.

• When we plot these coordinates and link them with straight lines, we can see that the simultaneous equations' solution is found at the position (2, 2) where the lines cross.

x + y = 4

2 + 2 = 4

2x - y = 2

4 - 2 = 2

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