Math, asked by ayaanshaikh56, 1 month ago

Solve the following simultaneous equations
(i) 4x + 3y = 18; 3x – 2y = 5.
(ii) 2x - y=5; 3x + 2y = 11.
Hil) 2x – 3y = 10; 4x - 5y = 15.
(iv) 5x + 2y = 13; 4x – 3y = 15.
Ww3a - 2b = – 10; 2a + 3b = 2.​

Answers

Answered by LakshyaSingh2005
1

Answer:

Sorry I don't now the answer of your question is that I am not a good maths student


ayaanshaikh56: That's Fine
Answered by sakshi4019
4

Step-by-step explanation:

ii) 2x-y=5; 3x + 2y =11

2x - y = 5..........(i)

3x + 2y =11.......(ii)

y = 5- 2x .........(iii)

substitute y = 5 - 2x in equation (ii)

3x + 2y =11

3x + 2( 5- 2x)=11

3x + 10 - 4x =11

3x - 4x = 11 -10

x = 1

put x = 1 in equation (i)

2x - y = 5

2(1) - y=5

2 - y = 5

y = 5-2

y = 3


ayaanshaikh56: thanks so much
sakshi4019: welcome
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