Solve the following simultaneous equations in two variables by the method of comparison
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Question :-
Solve the following simultaneous equations in two variables by the method of comparison
x/3 + y/4 = 1, 2x + 4y = 11
Required Answer :-
x/3 + y/4 = 1
Multiply throughout by 12 - (LCM)
12 x (x/3) + 12 x (y/4) = 12 x 1
4x + 3y = 12 -(i)
2x + 4y = 11 -(ii)
Multiply equation (ii) by 2
2x + 4y = 11
x 2
___________
4x + 8y = 22 - (ii)
subtracting equation (i) from (iii)
4x + 8y = 22
- 4x - 3y = -12
___________
5y = 10
y = 10/5
y = 2
put y = 2 in equation (i)
4x + 3y = 12
4x + 3(2) = 12
4x + 6 = 12
4x = 12 - 6
4x = 6
x = 6/4
x = 3/2
x = 1.5
Therefore, solution for (x, y) is (1.5,2)
Hope it help you :)
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