Question

Solve the following simultaneous equations
y + z = 2, 2x + 3z = 5, x + y + z = 3

Answer 1

We have y+z=2
Substituting it in the third equation
We have, x+2=3
Hence x=1
Substituting value of x in equation two we have,2+3z=5
Hence,z=1
Substituting value of z in equation one we have,y+1=2
Hence y=1

Answer 2

y+z=2

z=2-y-------(i)

put z=2-y in eq 2x+3z=5

2x+6-3y=5

x=1+3y/2--------(ii) (on simplifying the eq.)

put eq (i) & (ii) in eq ; x+y+z=3

-1+3y/2+y+2-y=3

-1+3y/2+2=3 (on simplifying the eq.)

-1+3y+4/2=3

-1+3y+4=6

-1+3y=2 (on simplifying the eq.)

3y=3

y=3---------(iii)

put eq (iii) in (i)

Z=2-1

Z=1---------(iv)

put eq (iii) &(iv) in equation x+y+z=3

x+1+1=3

x+2=3

x=1

So, X=1
Y=1
Z=1

If you like my answer mark me as BRAINLIST and follow me for more answer.