Question

solve the following simultaneous linear equation by elimination method : 11x-8y=27 ; 3x+5y= -7​

Answer 1

Answer:

$\mathtt{\huge{\underline{\red{Answer\: :}}}}$

Step-by-step explanation:

11x-8y=27

3x+5y=-7

multiply in equations (1) by 5 and (2) by8

55x-40y=135

24x+40y=-56

79x=79

x=1

3(1)+5y=-7

3+5y+7=0

5y+10=0

y=-10 is the answer of this question

Answer 2

${\huge{\underline{\underline{\tt{Answer \: \dag}}}}}$

$11x - 8y = 27 - - - (1) \\ \: 3x + 5y = - 7 - - - (2)$

${\underline{multiply \: (1) \: by \: 5 \: and \: (2) \: by \: 8}}$

$55x - 40y = 135 - - - (3) \\ 24x + 40y = - 56 - - - (4)$

${\underline{add \: (3) \: and \: (4)}}$

$79x = 79$

$x = \frac{79}{79}$

${\bold{\underline{\underline{x = 1}}}}$

${\underline{put \: x = 1 \: in \: (1)}}$

$11(1) - 8y = 27$

$11 - 8y = 27$

$11 - 27 = 8y$

$8y = - 16$

$y = \frac{ - 16}{8}$

${\bold{\underline{\underline{y = - 2}}}}$

${\underbrace{\red{hope \: u \: found \: it \: helpful}}}$