Math, asked by arunimakispotta, 5 months ago

solve the following simultaneous linear equations 3x+2y=11 , 2x-3y+0=10​

Answers

Answered by kunal171276
1

Answer:

3x +2y = 11 =1 equation by substitution method

x=11-2y /3

Answered by rakshitd363
3

Step-by-step explanation:

at first ..

3x+2y = 11

3x = 11-2y

x = 11-2y/3... (1)

next..

2x - 3y =10

2x=10 + 3y

x = 10 + 3y/2..(2)

then....

(1) and (2) compare

11-2y/3=10+3y/2

22-4y=30+9y

-4y-9y=30-22

-5y=8

y=8/-5

therefore..

x=21/5

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