solve the following simultaneous linear equations 3x+2y=11 , 2x-3y+0=10
Answers
Answered by
1
Answer:
3x +2y = 11 =1 equation by substitution method
x=11-2y /3
Answered by
3
Step-by-step explanation:
at first ..
3x+2y = 11
3x = 11-2y
x = 11-2y/3... (1)
next..
2x - 3y =10
2x=10 + 3y
x = 10 + 3y/2..(2)
then....
(1) and (2) compare
11-2y/3=10+3y/2
22-4y=30+9y
-4y-9y=30-22
-5y=8
y=8/-5
therefore..
x=21/5
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