Question

Solve the following simultaneous linear equations:

4x + 3y - 4 = 0

6x = 8 - 5y​

Answer 1

Given :

4x + 3y - 4 = 0

6x = 8 - 5y

To find :

x = ? , y = ?

Solution :

4x + 3y - 4 = 0 ------- × ( 6 )

6x = 8 - 5y ==> 6x + 5y - 8 = 0 ------ × ( 4 )

24x + 18y = 24

24x + 20y = 32

Subtract first equation from second equation for the value of y :

=> ( 24x + 20y ) - ( 24x + 18y ) = 32 - 24

=> 2y = 8

=> y = 4

Put y = 4 in 4x + 3y - 4 = 0

4x + 3y - 4 = 0

4x + 3× 4 - 4 = 0

4x + 12 - 4 = 0

4x + 8 = 0

4x = - 8

x = - 2

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Answer 2

Answer:

y=2 , x=-1/2

Step-by-step explanation:

4x + 3y - 4 = 0_ (1)

6x = 8 - 5y​ _(2)

4x+3y=4

6x+5y=8

x=(4-3y)/4

putting  the value of x in eq 4

6((4-3y)/4)+5y=8

(12-9y)/3+5y=8

4-3y+5y=8

2y=4

y=2

putting the value of y in eq 5

x=(4-6)/4

x=-1/2