Question

Solve the following simultaneous linear equations:

6x - 4y = - 12

8x - 3y = - 2​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$given \: \\ \\ 6x - 4y = - 12 \: \: \: \: -i \\ 8x - 3y = - 2 \: \: \: - ii \\ \\ so \: balancing \: eq \: i \: and \: ii \\ \\ multiplying \: eqn \: i \: by \: 3 \\ and \: eqn \: ii \: by \: 4 \\ (6x - 4y = - 12)3 \\ (8x - 3y) = - 2)4\\ \\ 18x - 12y = - 36 \\ 32x - 12y = - 8 \\ - \: \: \: \: \: \: + \: \: \: \: \: \: \: \: \: \: \: \: \: + \\ \\ - 14x = - 28 \\ \\ \\ x = \frac{ - 28}{ - 14} \\ \\ x = 2 \: \: \: \: \: \: (minus \: cancel \: \\ out) \\ \\ \\ fitting \: value \: of \: x \: \\ in \: eq - i \: \\ \\ 6 \times (2) - 4y = - 12 \\ \\ 12 - 4y = - 12 \\ - 4y = - 12 - 12 \\ \\ - 4y = - 24 \\ \\ y = \frac{ - 24}{ - 4 } \\ \\ y = 6 \\ x = 2 \\ \\ \\ ( - and - \: will \: cancell \\ out)$

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